Question

a convex mirror always a real image ☺why​

Answer 1

Answer :

The convex mirror diverges the given incident rays of light so that they do not actually meet at a particular point .

If the rays are produced backwards then they will meet at a point and hence we can obtain the image .

This kind of image cannot be obtained on a screen

Hence the convex mirror always forms a virtual image .

➡ A real image is always formed by the actual intersection of the light rays . A virtual image is formed when the light rays do not meet but when produced backwards they meet at a point .

➡ A real image can be obtained on a screen but a virtual image cannot be obtained on a screen .

➡ A real image is always inverted while a virtual image is always erect .

Answer 2

Your question is wrong

The actual question is =>

A convex lens always forms a virtual image. Why?

ANSWER

First, we will try to understand the meaning of Virtual image and Real image.

Virtual Image

-The image which is actually not formed, it just appears to form.

-It can't be obtained on the screen.

Real image

-It is the image which is actually formed.

-It can be obtained on a screen.

A convex mirror always forms a virtual image because =>

1)Convex mirror is a diverging mirror and the rays of light never meet in a point and hence there is no chance of real image formation.

2)But the rays appear to meet at a point behind the mirror and this is Virtual Image.

3)In the convex mirror there can be only 2 possible image formations=>

i) When Object is in infinity (u=-$\infty$ )

-The image formed is erect and virtual.

-The image is smaller in size than Object.

-The image appears to meet in principal focus.

ii) When Object is in between infinity and pole(-$\infty$<u<pole)

-The image is erect and virtual.

-The image is smaller in size than Object.

-The image appears to meet before the principal focus

Hence in both cases, the image formed is virtual and erect.