Question

A convex mirror has an object placed 25cm in front of it. An image is formed 45 cm from the mirror. What is the nature of the image? Calculate the magnification of the image and the focal length of the mirror.

Answer 1

The formed image is virtual, erect and smaller by size.

Magnification, m = 1.8

Focal length, f = 16.071 cm

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Explanation:

It is given that,

• Object distance, u = -25 cm
• Image distance, v = +45 cm (in front of the mirror)

If f is the focal length of the mirror. It can be calculated using mirrors formula as :

$\sf{ \red{\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}}} \\ \\ \sf \: \dfrac{1}{f}=\dfrac{1}{(-25)}+\dfrac{1}{(45)} \\ \\ \sf \: LCM \: of \: 25 \: and \: 45 \: is \: 225 \\ \sf \: \frac{1}{f} = \frac{ 9 + 5}{225} \\ \\ \sf \: f = 16.071 cm$

If m is the magnification of the mirror. Then,

Magnification

$\sf{ \red{m = \frac{ - v}{u} }} \\ \\ \sf \: m = \frac{45}{25} \\ \\ \sf \: m = 1.8$

• Magnification, m = 1.8
• Focal length, f = 16.071 cm

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Answer 2

Answer:

answer is  allah

Explanation:

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