A convex mirror has radius of curvature 3m . If the object is located 5m from the mirror Find the position,nature,and size of image
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Answered by
44
f = 3/2
U = -5
V= ?
We know, 1/f = 1/v + 1/u
1/v = 1/f - 1/u
1/v = 3/2 - (-1/5)
1/v = 3/2 + 1/5
1/v =( 15 + 2) /2
1/v = 17/2
v = 2/17
Image is highly diminished and Virtual and Erect
U = -5
V= ?
We know, 1/f = 1/v + 1/u
1/v = 1/f - 1/u
1/v = 3/2 - (-1/5)
1/v = 3/2 + 1/5
1/v =( 15 + 2) /2
1/v = 17/2
v = 2/17
Image is highly diminished and Virtual and Erect
Alabhya1273:
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Answered by
0
Answer:
R=+3
F=3
2
1/F = 1/V + 1/U
1/V =3/2 + 1/5
1/V = (15+2)/2
1/V = 17/2
V = 2/17
hence image formed is virtual & erect and highly diminished
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