A convex mirror of focal length 50 cm produces an image of height 6 cm at a distance of 25 cm . Find the height and the distance of the object from the mirror.
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Hi...
Use the mirror equation:
1/di + 1/do = 1/f
where di = +25 cm and f = +50 cm.
Substitute and solve for do.
1/do + 1/(25 cm) = 1/(50 cm)
1/do = 1/(50 cm) - 1/(25 cm) = -1/(50 cm)
do = - 50 cm..
Magnification = - v/u
Thus M= -25/-50=0.5..
M=h'/h
h'=M×h
h'=0.5 × 6= 3cm....
Hope this helps u!
Use the mirror equation:
1/di + 1/do = 1/f
where di = +25 cm and f = +50 cm.
Substitute and solve for do.
1/do + 1/(25 cm) = 1/(50 cm)
1/do = 1/(50 cm) - 1/(25 cm) = -1/(50 cm)
do = - 50 cm..
Magnification = - v/u
Thus M= -25/-50=0.5..
M=h'/h
h'=M×h
h'=0.5 × 6= 3cm....
Hope this helps u!
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