Question

A convex mirror of focal longh
9cm produces an image on its
axig 6cm from the mirror
determine the Position of the
object​

Answer 1

Given, u=-6cm, f=+12cm

Given, u=-6cm, f=+12cmto be find out, v=?,

Given, u=-6cm, f=+12cmto be find out, v=?,Using mirror formula

Given, u=-6cm, f=+12cmto be find out, v=?,Using mirror formula1/v = 1/f - 1/u

Given, u=-6cm, f=+12cmto be find out, v=?,Using mirror formula1/v = 1/f - 1/u1/v = 1/12 - 1/-6

Given, u=-6cm, f=+12cmto be find out, v=?,Using mirror formula1/v = 1/f - 1/u1/v = 1/12 - 1/-61/v =1/4

Given, u=-6cm, f=+12cmto be find out, v=?,Using mirror formula1/v = 1/f - 1/u1/v = 1/12 - 1/-61/v =1/4V=4 cm behind the mirror

Given, u=-6cm, f=+12cmto be find out, v=?,Using mirror formula1/v = 1/f - 1/u1/v = 1/12 - 1/-61/v =1/4V=4 cm behind the mirrorSo, the nature of the image is Virtual.

Given, u=-6cm, f=+12cmto be find out, v=?,Using mirror formula1/v = 1/f - 1/u1/v = 1/12 - 1/-61/v =1/4V=4 cm behind the mirrorSo, the nature of the image is Virtual.THANK YOU..

Answer 2

Answer:

$in \: convex \: mirror \: focal \: length \: is \: positive \\ image \: distance \: is \: also \: positive$

$so \: \frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

$f = 9cm \: and \: v = image \: distane = 6cm$

$\frac{1}{9 } = \frac{1}{u} + \frac{1}{6}$

$\frac{1}{u} = \ \frac{ - 1}{18}$

$so \: object \: distance \: is \: - 18cm$

here '-' indicates that direction of object.