A convex mirror produces a magnification of 1/2 when an object is placed at a distance of 60 cm in front of it. Where should the object be placed, so that the size of the image becomes 1/3 of that of the object?
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my answ3r is -90 cm.............
plzz mark it as a brainliest answer........
plzz mark it as a brainliest answer........
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Answer:The object should be placed in front of the mirror,at a distance of 120cm.
Explanation:
m=+1/2
U=-60cm
So, -v/u = +1/2
Or v= -u/2=-(-60)/2=30cm
1/f=1/v+1/u=1/30-1/60=(2-1)/60=1/60
Implies that f=60cm
Now,m=+1/3
-v/u=1/3
-v=u/3
v=-u/3
1/f=1/v+1/u
1/60=1/(-u/3)+1/u=-3/u+1/u=(-3+1)/u=-2/u
Implies that u=-2*60=-120cm.
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