a convex mirror produces a magnification of 1/2, when the object is placed at a distance of 0.60m from it. where must an object be placed so that size of the image becomes 1/3 of the object.
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Answered by
78
u=-60cm
m=1/2
m=-v/u
1/2=-v/-60
-v=-30cm
v=30cm
f=?
by mirror formula:
-1/60+1/30=1/f
on solving:
f=60cm
m=1/3
1/3=-v/u
v=(1/3)u
f=60cm
using mirror formula:
1/u+1/v=1/f
1/u-3/u=1/60
u=-120cm
HOPE IT HELPS..........
# @OOOIRKIOOO #
IF IT HELPS PLS MARK ME AS BRAINLIEST...................................
m=1/2
m=-v/u
1/2=-v/-60
-v=-30cm
v=30cm
f=?
by mirror formula:
-1/60+1/30=1/f
on solving:
f=60cm
m=1/3
1/3=-v/u
v=(1/3)u
f=60cm
using mirror formula:
1/u+1/v=1/f
1/u-3/u=1/60
u=-120cm
HOPE IT HELPS..........
# @OOOIRKIOOO #
IF IT HELPS PLS MARK ME AS BRAINLIEST...................................
Answered by
2
Here is the answer.Thank You.
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