Question

A convex mirror produces an image of half size when the object is kept at 25 cm from it. Where should the object be kept so that the size of image is one-third then the size of the object?





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Answer 1

Answer:

intial object distance u = -60cm(real object_)

magnification m =−  

2

1

​  

 

from m=  

u−f

−f

​  

 

from above f=−20cm

let the object distance be u  

′

 

magnification m  

′

=2× image of virtual real object

m=  

u  

′

−f

−f

​  

 

2=  

u  

′

+20

20

​  

⟹u  

′

=10cm

hence the object should be at a distance of 10cm infront of the mirror

Explanation:

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Answer 2

Answer:

Refer the above attachment

Explanation:

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