Physics, asked by rjrahul1234, 11 months ago

a convex mirror used as a rear view mirror in a car has a radius of curvature of 3 m . if a bus is located at a distance of 5 from this mirror ,find the position of image . what is the nature of the image

Answers

Answered by fazizazaza
5

Answer:

Explanation:

object distance (u)= -5m (always negative)

radius of curvature C = 3m

focal length = 3/2 = 1.5m.

with formula we know that ,

1/v +1/u = 1/f

1/v = 1/1.5 - 1/-5

1/v = -5 - 1.5 /-7.5

1/v = -6.5/-7.5

v = 1.15m

we must find magnification,

m= -v/u

= -1.15/-5

=0.23 

the image is formed on the opposite side of the object.so it will be virtual and erect.

and 0.23 is very small where the object is placed beyond C.

so the image is virtual ,diminished and erect.

Answered by Pratik021205
1

Answer:

R=+3m ⇒ f=  3/2m= 1.5m

U= −5m

By Mirror formula:

1/v+ 1/u = 1/f

1 /v +  1/(−5)  =  1/1.5

v

1

​  

=  

3

2

​  

+  

3

1

​  

 

v

1

​  

=  

15

13

​  

 

⇒v=  

13

15

​  

≃1.1538m behind the mirror

m=  

h  

o

​  

 

h  

I

​  

 

​  

=−(  

u

v

​  

)⇒h  

I

​  

=(  

u

−v

​  

)h  

o

​  

 

h  

I

​  

=(  

13

15

​  

×  

(1.5)

1

​  

)h  

o

​  

 

h  

I

​  

=  

13

3h  

o

​  

 

​  

 ie. diminished & virtual & erect

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