A convex mirror used for a rear view on an automobile has a radius of curvature of 3.0m. If a bus is located at 5.0m find the position and nature size of an image.
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given :
R=3m
f=R/2=3/2=1.5m
u=5m
v=?
Mirror formula:
1/f=1/u+1/v
by sign conventions:
1/1.5=1/-5+1/v
1/v=1/1.5+1/5⇒6.5/7.5
v=7.5/6.5
=1.15m
∴The image is virtual seen at the back of mirror.
m=hi/ho=-v/u
-1.15/-5=0.23
∴Image is erect and diminished in size by a factor of 0.23
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Image is formed 1. 15 m from the mirror
Nature of the image : virtual erect and dimished
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