a convex mirror used for rear view mirror in automibiles has radius of curvature 1 m.if the bus is 10 m from this mirror find the position, size and nature of the image
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Explanation:
radius of curvature R=+1m
object distance. u = -10m
image distance v= ?
height of the image h= ?
focal length f = R/2= +1m/2 = 0.5 (as the principal focus of a convex mirror is behind the mirror)
since l/v +1/u =1/ f
or. 1/v _1/u =1/f
= +1/0.50- 1/(-10.00)
=1/0.5 + 1/10.00)
= 10 +0.5/5
v=+5/4 = 1.25m
the image is 1.25m at the back of the mirror
magnification m =h'/h= -h'/h
= -1.25m/-10m
=+0.125
the image is virtual erect and smaller in size by a factor of 0.23
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