A convex mirror used for rear - view on an automobile has a radius of curvature of 3.00m. if a bis is located at 5.00 m from this mirror ,find the position,nature and size of the image.
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Answer:
v=?
u=-5m
f=3/2. (R=2f)
using mirror formula
1/v+1/u=1/f
we have to find image distance
so the formula will be
1/v=1/f-1/u
putting values now
1/v=2/3-(-1/5)
1/v=2/3+1/5
1/v=13/15
(v=15/13)
now magnification
m=-v/u
m=-15/13x1/-5
(m=3/13)
image formed is virtual and erect
Answered by
0
Answer:
v=?
u=-5m
f=3/2. (R=2f)
using mirror formula
1/v+1/u=1/f
we have to find image distance
so the formula will be
1/v=1/f-1/u
putting values now
1/v=2/3-(-1/5)
1/v=2/3+1/5
1/v=13/15
(v=15/13)
now magnification
m=-v/u
m=-15/13x1/-5
(m=3/13)
image formed is virtual and erect
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