Question

a convex mirror used for rear view on an automobile has a radius of curvature of 3.00m. if a bus is located at 5.00 from the mirror find the position,nature and size




also tell how to identify the size, whether it is smaller of larger

Answer 1

Hey!

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Radius of curvature (R) = 3 m
Focal length of convex mirror (f) = R/2
= 3/2 = 1.5 m

Distance of the object (bus) (u) = - 5 m
Image distance = ?

We know the mirror formula,

1/f = 1/v + 1/u
1/1.5 = 1/v + 1/ (-5)

1/v = 1/1.5 + 1/5
After calculating,

v = 1.15 m

Thus ,

Position of the image = 1.15 m behind the mirror. Image is virtual.


Magnification (m) = Image distance / Object distance

m = -v/u

= -1.15 / -5

= 0.23

Thus, The image is virtual, erect and smaller in size by a factor of 0.23.

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Hope it helps...!!!

Answer 2

Hey user

[ See the attached image for answer no . A ]

• Image is highly Diminished

• Right side of the object or in front of the 2F2

• image is Erect [ since Magnification is +ve ]

• ( Question B ) :- Is there anyway to find out the size of the image or object

or

• Describe the relationship between , magnification ,( m ) or Image distance( v ) and object distance ( u )


→ Answer :-


$magnification \: (m) = \frac{height \: of \: the \: image \: }{height \: of \: the \: object} = \frac{ - v}{u}$


Hope this helps you ☺