Question

A convex mirror used for rear-view on an automobile has a radius of curvature of 3.00 m. If a bus is located at 5.00 m from this mirror, find the position, nature and size of the image.​

Answer 1

Given:

Radius of curvature = 3.00 m

Bus located from this mirror = 5.00 m

Mirror formula:

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

Formula of magnification of a mirror:

$m = - \frac{v}{u}$

Here,

v is the distance of the image and u is the distance of the object from the mirror.

Solution:

u = 5m

r = 3m

f = r/2

f = 3/2

f = 1.5m

Now in the mirror formula:

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u} \\ \frac{6.5}{7.5}$

v = 1.15m

Magnification:

$m = - \frac{v}{u} \\ m = - \frac{ - 1.15}{ - 5} \\ m = 0.23$

Therefore, the size of the image on the convex mirror will be 0.23 times more than the bus (object).

The image formed will be:

• Erect
• Diminished

Answer 2

Refer the attachments....