A convex mirror used for rear view on an automobile has a radius of curvature of 3 metre if a bus is located at 5meter from this mirror then image distance is
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object distance (u)= -5m (always negative) radius of curvature C = 3m focal length = 3/2 = 1.5m.
with formula we know that,
1/v +1/u = 1/f
1/ v1/1.5-1/-5
1/v = -5 -1.5/-7.5
1/v-6.5/-7.5
v = 1.15m
we must find magnification,
m= -v/u
= -1.15/-5
=0.23
the image is formed on the opposite side of the object.so it will be virtual and erect. and 0.23 is very small where the object is
placed beyond C.
so the image is virtual,diminished and erect.
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