a convex mirror used for rear view on the automobile has the radius of curvature of 6m. if the car is located at 10m from the mirror, find the position , the nature and size of image
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C=6m f=C/2=6/2=3m
Using Mirror Formula,
1/f=1/v+1/u
f=3m, v=+v m, u=-10 m
1/3=1/v-1/10
1/v=1/3+1/10
1/v=10+3/30
1/v=13/30
v=30/13 m
Hence, Image is :
(i) Virtual,
(ii) Erect,
(iii) Diminished,
(iv) 30/13 m behind the mirror.
(v) Cannot be obtained on a screen.
The diagram is for better understanding but it is roughly drawn so sorry for that.
Using Mirror Formula,
1/f=1/v+1/u
f=3m, v=+v m, u=-10 m
1/3=1/v-1/10
1/v=1/3+1/10
1/v=10+3/30
1/v=13/30
v=30/13 m
Hence, Image is :
(i) Virtual,
(ii) Erect,
(iii) Diminished,
(iv) 30/13 m behind the mirror.
(v) Cannot be obtained on a screen.
The diagram is for better understanding but it is roughly drawn so sorry for that.
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Answered by
1
R = 2f
6÷2 = f
f = 3cm
u=-10cm
v=?
1÷v + 1÷u = 1÷f
1÷v = 1÷3 +1÷10
1÷v =13 ÷30
v = 30÷13
v=2.31 cm
The image is formed between the pole and the focus . the image is erect , diminished . The size of the image is lesser than the object.
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