a convex mirror used on a automobile has a radius of a curveture 3cm.if an object is at the distance 4.5m find (i) position (ii) nature (iii) magnification of the image
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Given: u=−20 cm
f=R/2=15 cm
Size of image, h=5 cm
Let size of image be h
′
From mirror formula,
u
1
+
v
1
=
f
1
−20
1
+
v
1
=
15
1
v=
7
60
=8.57 cm
The image is formed 8.57cm behind the mirror. It is virtual and erect.
Magnification, m=−v/u=8.57/20=0.428
Also, m=h
′
/h=h
′
/5
From above, h
′
/5=0.428
h
′
=2.14 cm
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