Question

a convex mirror used on a bus has a radius of curvature 2m if scooter is located at 600cm from this mirror find the position nature and magnification of the image formed in the mirror

Answer 1

curvature(R) = 2× 100 = 200cm
f = R/2= 200/2= 100cm
then , v = 120cm {by the mirror formula}
magnification(m) = -v/u
m= -( 120/-600)
m= -(-1/5)
m= 0.2
and nature of image is : virtual , erect , and diminshed

Answer 2

Answer:

r = 2m = 200 cm

u = -600

r= 2f

200=2f

100=f

by using mirror formula that is

1/f = 1/v+1/u we get

1/100 = 1/v +(-1)/600

now shifting -1/600 to left side we get

1/100+1/600 = 1/v

6+1/600 = 1/v

7/600 = 1/v

7v = 600

v = 600/7

v = 85.71

now magnification

using formula

-v/u (as it is mirror)

-85.71/-600

= 0.14

this is the answer thank you.