Question

a convex mirror which is used for rear view on an automobile has a radius of curvature of 3.0 if a bus is located at 5.0 from this mirror determine the position nature and magnification of the image​

Answer 1

Answer:

Position = 2.14units from the mirror

Nature = Real inverted

Magnification = -0.08

Explanation:

u = -5units

R = 3units

We know that,

f = 1/2R

===> f = 3/2 = -1.5units

According to mirror formula,

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

Therefore,

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u} \\ \frac{1}{v} = \frac{1}{-1.5} - \frac{1}{-5}$

$\\ = \frac{-5 + 1.5}{7.5} \\ = \frac{-3.5}{7.5}$

$\frac{1}{v} = \frac{-3.5}{7.5} \\ v = \frac{-7.5}{3.5} = -2.14$

m = -v/u

= -(-2.14)/-5

= -0.42

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For convex mirrors,

f = (-ve)

u = (-ve)

v = (-ve)

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Hope it helps.....!

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