a convex mirror with radius 3cm is used as rare view mirror force vehicle if a bus is located at 5cm from this mirror .find image
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2
object distance (u)= -5m (always negative)
radius of curvature C = 3m
focal length = 3/2 = 1.5m.
with formula we know that ,
1/v +1/u = 1/f
1/v = 1/1.5 - 1/-5
1/v = -5 - 1.5 /-7.5
1/v = -6.5/-7.5
v = 1.15m
we must find magnification,
m= -v/u
= -1.15/-5
=0.23
the image is formed on the opposite side of the object.so it will be virtual and erect.
and 0.23 is very small where the object is placed beyond C.
so the image is virtual ,diminished and erect.
hope it helps!!!!
radius of curvature C = 3m
focal length = 3/2 = 1.5m.
with formula we know that ,
1/v +1/u = 1/f
1/v = 1/1.5 - 1/-5
1/v = -5 - 1.5 /-7.5
1/v = -6.5/-7.5
v = 1.15m
we must find magnification,
m= -v/u
= -1.15/-5
=0.23
the image is formed on the opposite side of the object.so it will be virtual and erect.
and 0.23 is very small where the object is placed beyond C.
so the image is virtual ,diminished and erect.
hope it helps!!!!
suresh144:
thanks for ur INTELLIGENCE
Answered by
7
ANSWER:-----------------
R= 3.5
U= 10.0
f= R/2 =3.5/2
3.5°10/2°10
35/20
7/4
1.75
1/f= 1/v +1/u 1/v = 1/f- 1/u 1/v= 1/1.75-1/-10
= 1/7/4-1/-10 =4/7- 1/-10
= -40-7\ 70 = 47/70
v = 70\47
v = 1.5
m= -v\u
m = -1.5\[-10]
= 0.15 An
hope it helps:--
T!—!ANKS!!!
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