Question

A convex mirror with radius of curvature 30 cm forms a real image at 20 cm From its pole . Explain how it is possible and find whether the image is erect or inverted? ​

Answer 1

Answer:

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PHYSICS

An object of size 3 cm is placed at 30 cm in front of a concave mirror of radius of curvature 40 cm. Find the distance and size of image from the mirror and describe the nature of the image

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VIDEO EXPLANATION

ANSWER

Given,

Radius of curvature, R=40cm

Object distance, u=30cm

Object height, h

o

=3cm

The focal length of the mirror=f=−

2

R

=−20cm

From mirror equation,

v

1

+

u

1

=

f

1

⟹

v

1

+

−30

1

=

−20

1

⟹v=−60cm

The magnification, M=

u

−v

=−

−30

−60

=−2

Hence the image is inverted, enlarged, real and its size is 2×3cm=6cm.

Answer 2

Answer:

I m not sure about the answer please confirm me.