Question

a convex mirror with radius of curvature 5 metre is attached with motorcycle to see the object behind the motorcycle describe the position nature and size of the image formed by this mirror of another motorcycle Coming from behind at a distance of 5 metre​

Answer 1

The position nature and size of the image formed by this mirror of another motorcycle coming from behind at a distance of 5 metres is 1.67 m away from the object and virtual, diminished and erect.

Explanation:

The object distance, u = - 5 m

The radius of curvature, R = 5 m

∴ The focal length, f = $\frac{R}{2} = \frac{5}{2}$ = 2.5 m.

Let the image distance be denoted as "v" m.

Using the mirror formula, we have  

1/v + 1/u = 1/f

⇒ 1/v = 1/f – 1/u

⇒ 1/v = 1/2.5 – [1/(-5)]

⇒ 1/v = 1/2.5 + 1/5

⇒ 1/v = [5+2.5] /12.5

⇒ 1/v = 7.5/12.5

⇒ 1/v = 3/5

⇒ v = 5/3

⇒ v = 1.67 m

Now we will find the magnification,

m = - [v/u]

⇒ m = -[1.67/-5]

⇒ m = 0.334  

Thus, we can conclude that the image formed is on the opposite side of the object and will be very small where the object is placed beyond the radius of curvature. Hence the image is 1.67 m away from the object and is virtual ,diminished and erect.

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