Question

A convex mirror with the radius of curvature 4m is used as a rearview mirror in a car. If a truck is located at a distance of 6m from the mirror, find the position, nature and size of the image.

Answer 1

Answer:

refer to the attachment for the solution.

Answer 2

Answer:

Position of image is $1.5m$

Nature is virtual and erect.

The size of the image is smaller than the size of an object.

Explanation:

Given that

$u=6m$

$R=4m$

Hence, focal length $f=2m$

Using the mirror formula;

$\frac{1}{v} +\frac{1}{u} =\frac{1}{f}$

Using values,

$\frac{1}{v} +\frac{1}{6} =\frac{1}{2}$

$\frac{1}{v} =\frac{6+12}{12}$

Solving

$v=\frac{12}{8}$

$v=+1.5m$

Image is virtual and erect as sign is positive.

Magnification, $m=-\frac{u}{v}$

$m=-\frac{1.5}{-6}$

$m=+0.25$

#SPJ2