A convex polygon has 65 diagonals. find the number of sides of the polygon.
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No of polygon =n(n-3)/2=65
n^2-3n-130=0
⇒n-13n+10n-130=0
⇒(n-13)(n+10)=0
⇒n-13=0
⇒n=13
n^2-3n-130=0
⇒n-13n+10n-130=0
⇒(n-13)(n+10)=0
⇒n-13=0
⇒n=13
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