Question

a convex refracting surface of radius of curvature 20 cm separates 2 media of refractive indices 4/3 and 1.6. an object is placed in the first medium at a distance of 200 cm from the refracting surface . calculate the position of the image

Answer 1

Explanation:

Given a convex refracting surface of radius of curvature 20 cm separates 2 media of refractive indices 4/3 and 1.6. an object is placed in the first medium at a distance of 200 cm from the refracting surface. calculate the position of the image

• Given A convex refracting surface of radius of curvature 20 cm separates two medium of refractive indices 4/3 and 1.6.
• So R = 20 cm
• n1 = 4/3 = 1.33
• n2 = 1.6
• u = - 200 cm
• v = ?
• So the refraction is from rarer medium to denser medium.
• So refraction through a spherical interface will be  
• μ2 – μ1 / R = μ2 / v – μ1 / u  
• 1.6 – 1.33 / 20 = 1.6 / v – 4/3 / - 200
•                             = 1.6 / v + 1.33 / 200
•                 v = 2400 / 5 x 2.05
•                  v = 234.15 cm

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https://brainly.in/question/23567812