Question

A convex surface of radius of curvature R separates two media of refractive index {{\mu }_{1}}μ1​ and {{\mu }_{2}}μ2​an object is placed in the medium of refractive index {{\mu }_{1}}μ1​. The relation between the object and image position is​

Answer 1

Explanation:

jsufhidk a few minutes ago and Science

Answer 2

From Brewster's law

The refractive index of the medium is given by

n=tani

p

where i

p

= polarising angle

⇒n=tan60

o

⇒n=

3

If C be the critical angle for the medium then,

n=

sinC

1

sinC=

n

1

=

3

1

C=sin

−1

(

3

1

)

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