a cook uses a fire tong of length 35 cm to lift a piece of burning coal of mass 200g .if he applies his effort at a distance of 7 cm from the fulcrum,what is the effort in si unit
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load = 200g
effort =xg [let]
load arm =35 cm
effort arm=7 cm
now
M.A=effort arm /load arm
200/x = 7/35
x = 200 x 35/7
x=1000
the effort = 1000 g = 1kg
effort =xg [let]
load arm =35 cm
effort arm=7 cm
now
M.A=effort arm /load arm
200/x = 7/35
x = 200 x 35/7
x=1000
the effort = 1000 g = 1kg
moldydemigod:
ty so much
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