A cook uses the fire tongs 28 cm to lift a piece of burning coal of mass 250 grams. If he applies the effort at a distance of 7 cm from the fulcrum, find the effort.
{Take g = 10 ms^-2}
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___________________________
F. E. L
<-------------------------28cm------------------>
by the principal of lever ,we have .
effort×effort arm= load × load arm .
effort ×7=250 gf × 28=>
effort 1000gf= 1kgf =10 N.
ok
its help u...
___________________________
F. E. L
<-------------------------28cm------------------>
by the principal of lever ,we have .
effort×effort arm= load × load arm .
effort ×7=250 gf × 28=>
effort 1000gf= 1kgf =10 N.
ok
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