Science, asked by deepahsani, 7 months ago

A cooler of 1500 W, 200 volt and a fan of 500 W, 200 volt are to be used from a household supply. The rating of fuse to be used is *

Answers

Answered by mitalibisht285

1

Answer:

Total power used, P - P1 + P2 = 1500 + 500 = 2000 W.

Current drawn from the supply,

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