Physics, asked by besrapinky255, 9 hours ago

A cooler of 1500 W, 200 volt and a fan of 500 W, 200 volts are to be used from a household supply. The rating

of fuse to be used is

Answers

Answered by Anonymous

1

Answer:

Explanation:

Total power used, P = P1 + P1 = 1500 + 500 = 2000 W.

Current drawn from the supply,

I = P/V = 2000/200

= 10A

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