Question

A coolie lifts a luggage of 15kg from the ground and put it on his head . 1.5 meter above the ground. calculate the work done by him on the language .​

Answer 1

Mass of luggage (m) = 15 kg

Displacement (S) = 1.5 m

So, Work done, W = F × S

=mg*S[f=mg]

=15*10*1.5

[g=10m/s2]

[g=force of gravity]

=225.0kg m/s2

=225Nm=225J

work done =225J.

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Answer 2

Here the work done is zero because he lifts it perpendicular to its head
So,
W=Fscos Θ
W= Fscos90
W=0

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