Question

a copper aloy wire of 1.5 mm diameter and 30m along is hanging frele tower what will be its elongation take specfic of weight the copper wire as 89.2 km/m and 90GPa respectively

Answer 1

Answer:

L=2m,

L=2m,d=3mm,A=

L=2m,d=3mm,A= 4

L=2m,d=3mm,A= 49π

L=2m,d=3mm,A= 49π

L=2m,d=3mm,A= 49π ×10

L=2m,d=3mm,A= 49π ×10 −6

L=2m,d=3mm,A= 49π ×10 −6 m

L=2m,d=3mm,A= 49π ×10 −6 m 2

L=2m,d=3mm,A= 49π ×10 −6 m 2

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL=

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 4

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5

L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm

Explanation:

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