Question

A copper atom consists of copper nucleus surrounded by 29 electron the atomic weight of copper is 63.5g/mole let us now take two piece of copper each weighing 10g and transfer one electron from one piece to another for every 1000 atom's in that piece, then calculate the mangnitude of charge on each piece​

Answer 1

Answer:

Explanation:

No. of atoms in 10g of copper

n=  

63.5

10

​

×6×10  

23

=9.448×10  

22

 

Number of electrons transferred,

N=  

1000

n×1

​

=9.448×10  

19

 

(a) Magnitude of charge appearing on either piece

q=Ne=9.448×10  

22

×1.6×10  

−19

=15.12C

(b) F=k  

r  

2

 

q  

2

 

​

=  

(0.10)  

2

 

9×10  

9

×(15.12)  

2

 

​

=2.05×10  

14

N