Question

A copper ball at 30 degree Celsius put in the container containing water at 30 degree celsius in this case option ​

Answer 1

Answer:

The temperate will be 60°C

Answer 2

Answer:

There will be no change in the final temperature

Given:

The temperature of the copper ball = 30°

The temperature of water = 30°

To find:

The temperature when the copper ball is dropped into water

Explanation:

The temperature difference between the copper ball and water = 30 – 30 = 0°

There will be no temperature when the copper ball is dropped into water.

But since the ball is dropped into the water from the air, the ball will interact with the atmospheric temperature due to potential energy and hence there will be a slight decrease in temperature which is negligible. Hence, the final temperature will remain the same.