A copper ball of density 8.6 g/cm3, 1 cm in diameter is immersed in oil of density 0.8 g/cm3
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Hey dear,
You left the question incomplete.
● Complete question will be -
A copper ball of density 8.6 g/cm3, 1 cm in diameter is immersed in oil of density 0.8 g/cm3. Calculate the mass of oil displaced by copper ball.
● Answer -
M = 0.4189 g
● Explaination -
As the copper ball have much higher density than oil, it will get completely immersed in the oil.
Oil displaced is given by -
Volume of oil displaced = Volume of ball
V = 4/3 πR^3
V = 4/3 × π × (0.5)^3
V = 0.5236 cm^3
Mass of oil displaced is calculated by -
M = V × ρ
M = 0.5236 × 0.8
M = 0.4189 g
Therefore, 0.4189 g of oil will be displaced out.
Hope this helps you...
You left the question incomplete.
● Complete question will be -
A copper ball of density 8.6 g/cm3, 1 cm in diameter is immersed in oil of density 0.8 g/cm3. Calculate the mass of oil displaced by copper ball.
● Answer -
M = 0.4189 g
● Explaination -
As the copper ball have much higher density than oil, it will get completely immersed in the oil.
Oil displaced is given by -
Volume of oil displaced = Volume of ball
V = 4/3 πR^3
V = 4/3 × π × (0.5)^3
V = 0.5236 cm^3
Mass of oil displaced is calculated by -
M = V × ρ
M = 0.5236 × 0.8
M = 0.4189 g
Therefore, 0.4189 g of oil will be displaced out.
Hope this helps you...
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