Question

A copper ball originally at 80degree celcius cools down at 60degree celcius in 20 min if the air tempurature is 40degree celcius what will be the temperature of the ball after 40 min from the original ​

Answer 1

Answer:

Found this

Step-by-step explanation:

Hope it helps u

Answer 2

Answer:

Concept :

A measure of the average kinetic energy per atom or molecule in the system, temperature is a physical term that reflects how hot stuff is. All matter contains this observable amount of molar thermal energy; heat is a movement of energy from a hotter body to a cooler body due to temperature differences. A thermometer is used to measure temperature, and several temperature scales have been calibrated using different reference points and thermometric substances in the past.

Explanation:

Given :

t=20mins

t1=80° C

t2=40°C

T=60° C

To find :

Total 40 mins =  ?

Solution :

T= t2 + (t1-t2) $e^{-kt}$

60 = 40 + (80-40)$e^{-k}$ × 20

60 - 40 = 40 $e^{-20k}$

20 = 40 $e^{-20k}$

$e^{-20k}$ =20/40

$e^{-20k}$ =1/2

$e^{-20k}$ =1/2

20K = log2

K = 0.3010/2

K =0.01505

T= t2 + (t1-t2) $e^{-kt}$

T= 40 + 40 $e^{-(0,0150)(40)}$

T= 40 + 40$e^{-0.6}$

T= 40 + 21.952

T= 61.952°C

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