Question

A copper ball requires 4500 joule heat energy to raise its temperature by 15 degree c. Calculate the heat capacity of the iron ball

Answer 1

Answer:

Answer:

Q = 4500 J

t = 15°c

Heat capacity C' = Q/t

C' = 4500/15

C' = 300 J/C

Answer 2

$\star$ Given:

A copper ball requires 4500 joule heat energy to raise its temperature by

15 °C

$\star$ To Find:

The Heat capacity of the iron ball

$\star$ Solution:

We know that,

$\red{\bigstar \ \boxed{\rm C=\dfrac{Q}{\Delta T}}}$

Here,

• C = Heat capacity

• Q = Heat energy required

• ΔT = Change in temperature

According to the Question,

We are asked to find the Heat capacity of the iron ball

So, we must find "C"

Given that,

A copper ball requires 4500 joule heat energy to raise its temperature by

15 °C

Hence,

• Q = 4500 J

• ΔT = 15 °C = 15 K

Substituting the values,

We get,

$\blue{\rm \implies C=\dfrac{4500}{15} \ J/K}$

On further simplification,

$\pink{\rm \implies C=300 \ JK^{-1}}$

Hence,

$\orange{\checkmark \ \rm Heat \ Capacity = 300 \ JK^{-1}}$