Question

A copper block of 2 kg is heated in a furnace from 30°C to 430°C and then placed on thick ice block. Calculate specific heat of copper if ice melted is 1Kg​

Answer 1

Answer:

PHYSICS

A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500

o

C and then placed on a large ice block. What is the maximum amount of ice that can melt ? (Specific heat of copper=0.39Jg

−1

K

−1

; heat of fusion of water =335Jg

−1

)

November 22, 2019avatar

Mitesh Ramekar

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VIDEO EXPLANATION

ANSWER

Mass of the copper block, m=2.5kg=2500g

Rise in the temperature of the copper block, =500

o

C

Specific heat of copper, C=0.39J/g

o

C

Heat of fusion of water, L=335J/g

The maximum heat the copper block can lose,

Q=mC

=2500×0.39×500

=487500J

Let m

1

g be the amount of ice that melts when the copper block is placed on the ice block.

The heat gained by the melted ice,Q=m

1

L

m

1

=Q/L=487500/335=1455.22g

Hence, the maximum amount of ice that can melt is 1.45 kg