Question

A copper block of mass 1 kg slides down on a rough inclined
speed. Find the increase in the temperature of the block as it slides
down on a rough inclined plane of inclination 37° at a constant speed
Find the increase intemperature of the block as it slides down through 60cm assuming
that the loss in mechanical energy goes into the copper block
mechanical energy goes into the copper block as thermal energy. (Specific heat of
copper = 420 J kg-'K-, g = 10ms)​
plz ansr I'll give them the branliest

Answer 1

Answer:

The answer will be 8.6×10^(−3)°  C

Explanation:

Let increase in temperature while sliding down, making angle  is △t

Now we know, Work done by the block is equal to the loss in mechanical energy.

Let the loss in mechanical energy be △E

Therefore,

△E = W

    = mg sinθ x l

Now we know that the absorbed heat energy is,

Q=mc△t

Ler Q and △E  is equal

Therefore,

mc△t = mg sinθ x l

=> △t  = g sinθ x l /c

          now putting the g = 10 m/s^2 , θ  = 37°  , l = 60 cm or 0.6 m and c = 420 kg-'K-

=> △t = 10 x sin 37 x 0.6/420

        =8.6×10^(−3)°  C