Question

A copper calorimeter contains 100 grams of water at 16 degree Celsius when 15 grams of ice is added to that the resultant temperature of the mixture is 4 degree Celsius water equivalent of the calorimeter is

Answer 1

weight of water equivalent is 5g

mass of water , M = 100g

initial temperature of water, T_i = 16°C

the mass of ice is m = 15g is added so that resultant temperature of the mixture would be T_f = 4°C.

let water equivalent of the calorimeter is m.

heat released by water and water equivalent = (m + 100) × s × (T_i - T_f)

= (m + 100) × 1 × (16 - 4)

= 12(m + 100)

heat gained by ice = 15g × 80cal/g + 15 × 1 × (4 - 0) [ at first ice melts and then change its temperature from 0°C to 4°C ]

= 1200 + 60

= 1260

now, heat released = heat gained

⇒12(m + 100) = 1260

⇒m + 100 = 105

⇒m = 5g

hence, weight of water equivalent is 5g

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Answer 2

$\huge\bold\purple{Answer:-}$

mass of water , M = 100g

initial temperature of water, T_i = 16°C

the mass of ice is m = 15g is added so that resultant temperature of the mixture would be T_f = 4°C.

let water equivalent of the calorimeter is m.

heat released by water and water equivalent = (m + 100) × s × (T_i - T_f)

= (m + 100) × 1 × (16 - 4)

= 12(m + 100)

heat gained by ice = 15g × 80cal/g + 15 × 1 × (4 - 0) [ at first ice melts and then change its temperature from 0°C to 4°C ]

= 1200 + 60

= 1260

now, heat released = heat gained

⇒12(m + 100) = 1260

⇒m + 100 = 105

⇒m = 5g

hence, weight of water equivalent is 5g