Question

A copper coin has mass of 63g. Calculate nuclear binding energy. The coin is entirely made of Cu^63 atoms
Mass of Cu^63 atom=62.92960
Mass of proton =1.00727
Mass of Neutron =1.00866
Avogadro number=6.022×10^23

Answer 1

Answer:

Binding energy of copper coin is given as

$BE = 5.16 \times 10^{13} J$

Explanation:

Mass of the copper coin is given as m = 63 g

atomic mass of the copper is given as M = 62.92960 gm/mol

now the number of moles is given as

$n = \frac{m}{M} = 1 mole$

total number of atoms is given as

$N = n \times N_a$

$N = 6.022 \times 10^{23}$

Binding energy of one copper atom is given as

$BE = (zm_p + (A - z)m_n - M)c^2$

$BE = (29(1.00727) + 34(1.00866) - 62.92960)c^2$

$BE = 535.95 MeV$

Binding energy of all atoms is given as

$BE = (6.022 \times 10^{23})(535.95 \times 1.6 \times 10^{-13})$

$BE = 5.16 \times 10^{13} J$

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Topic : Binding Energy

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