a copper coin is kept immersed in a solution of silver nitrate for some time. what will happen to the coin and to the solution
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. The silver nitrate is in solution and the metallic copper will dissolve to form copper nitrate; as it does so, the silver in solution will be precipitated out as metallic silver. That is, the silver in solution is exchanged for copper and the copper that is not in solution is substituted for silver. Hope this makes sense!
Cu(0) + 2AgNO3 = Cu(NO3)2 + Ag(0)
Cu(0) + 2AgNO3 = Cu(NO3)2 + Ag(0)
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Copper coin will react with the silver nitrate solution as it more reactive tha silver.
Cu+AgNO3 -> CuO + Ag + NO2
Cu+AgNO3 -> CuO + Ag + NO2
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