A copper conductor has a number density of free electrons estimated of 8.5 10 28 m 3. The area of the cross-section of the wire is 2.010 6 m 2 and it is carrying a current of 3.0
a. Find the drift velocity. How long does an electron take to drift from one end of a wire 3.0 m long to its other end?
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Calculate the drift velocity Vd=IneAVd=IneA
Given n=85×1028/m3n=85×1028/m3
A=2×10−6m2A=2×10−6m2
I=3AI=3A
e=1.6×10−7Ce=1.6×10−7C
Time taken by electron to drift from one end to continue of the wire,
t=length of the wiredrift velocityt=length of the wiredrift velocity
=lVd
Use the relation ,
I=neAVdI=neAVd
=> Vd=IneAVd=IneA
t=lneAIt=lneAI
substituting the values we get,
t=lneAIt=lneAI
=3×8.5×1028×1.6×10−19×2×10−63=3×8.5×1028×1.6×10−19×2×10−63
∴t=2.72×104S∴t=2.72×104S
==7 hours and minute
The time taken by an electron to drift from one end to another end is 7 hours and 33 mins
Given n=85×1028/m3n=85×1028/m3
A=2×10−6m2A=2×10−6m2
I=3AI=3A
e=1.6×10−7Ce=1.6×10−7C
Time taken by electron to drift from one end to continue of the wire,
t=length of the wiredrift velocityt=length of the wiredrift velocity
=lVd
Use the relation ,
I=neAVdI=neAVd
=> Vd=IneAVd=IneA
t=lneAIt=lneAI
substituting the values we get,
t=lneAIt=lneAI
=3×8.5×1028×1.6×10−19×2×10−63=3×8.5×1028×1.6×10−19×2×10−63
∴t=2.72×104S∴t=2.72×104S
==7 hours and minute
The time taken by an electron to drift from one end to another end is 7 hours and 33 mins
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