Question

A Copper Conductor of area of cross section 40mm square carries a constant current of 32×10^-6A. then the current density is​

Answer 1

Explanation:

using formula

j=I/A

= 32×10^-6/40×10^-6=16/20=4/5

Answer 2

Answer: Current density is 0.8 A/m²

Explanation:

Area of cross section of copper conductor = 40  mm²

Area of cross section of copper conductor = 40 × 10⁻⁶ m²

Area of cross section of copper conductor = 4 × 10⁻⁵ m²

Current flowing through the copper conductor = 32 × 10⁻⁶ A

Current density is defined as current (I) flowing per unit area (A) of a material.

It is denoted by the symbol J.

J = $\frac{I}{A}$

Current density is also defined as product of charge density (σ) and velocity of charge (v)

J = σv

Current density = Current/Area

Current density of copper conductor =  (32 × 10⁻⁶ ) / (4 × 10⁻⁵)  A/m²

Current density of copper conductor =  8 × 10⁻¹ A/m²

Current density of copper conductor = 0.8 A/m²

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