Question

A copper cube 0.30m on a side is subjected
to a shearing force of F = 6.0x10power 6N. Assuming
that the shear modulus for copper is
4.2x10power 10N/m². The angle through which the
cube shear is (approximately)
[1]
1) 0.090
2) 0.150
3) 0.210
4) 0.329​

Answer 1

haa guys ..Hello!!

1. l=b=h=0.3
2. A=l*b
3. A=(0.3)(0.3)
4. F=6*10 to the power 6N
5. shear module=4.2*to the power 10N/m
6. shear module =F/A Theta
7. theta=F/A*shear module
8. =10 to the power 6/9*10 to the power of -2*4.2*10 to the power of 10
9. 0.01587 N/m square
10. 0.09degree

soo"..

guys! hope it's useful

Answer 2

Answer:

0.090

Explanation:

Hope it is the correct answer