Question

A copper cube of mass 0.5kg is weighted in water. The mass comes out to be 0.4 kg. Find density of cube?​

Answer 1

Explanation:

A copper cube of mass

0.5kg

is weighed in water. The mass comes out to be

0.40kg

Is the cube hollower solid ? Given density of copper

8.96*10³kgm-³

and density of water

=10³kgm-³

Answer 2

The density of the cube is 5000 kg/m^3.

Given:

Mass=.5kg

To find:

Density of cube.

Solution:

We know,

Density = Mass / Volume

Given,

M=0.5 kg,

The cube weighs 0.4 kg and its submerged in water.

The buoyant force acting on the cube= The weight of water.

Weight of water = Density of water x Volume of water x gravitational acceleration

So,

Buoyant force = Weight of water

                        = Density of water x Volume of cube x gravitational acceleration

We know,

The weight of the cube( air)= 0.5 x 9.81

                                             = 4.905 N

The weight of the cube ( water) =0.4 x 9.81

                                                     = 3.924 N

Buoyant force = Weight of cube in air - Weight of cube in water

⇒Density of water x Volume of cube x gravitational acceleration = 4.905 - 3.924

As we know,

Density of water = 1000 kg/m^3.

Now after putting the values,

Density of water x Volume of cube x gravitational acceleration  = 0.981

⇒Volume of cube = 0.981 / (1000 x 9.81)

                              = 0.0001 m^3

Now ,

Density = Mass / Volume

             = 0.5 / 0.0001

             = 5000 kg/m^3

So the density of the cube is 5000 kg/m^3.

#SPJ3