Question

A copper cylinder has a mass of 76.8 g and a specific heat of 0.092 cal/g·C. It is heated to 86.5° C and then put in 68.7 g of turpentine whose temperature is 19.5° C. The final temperature of the mixture is 31.9° C. What is the specific heat of the turpentine?​

Answer 1

Answer:

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Answer 2

The specific heat of the turpentine is $0.45\frac{cal}{g^{0}c}$.

Explanation:

$(76.8g)(0.092\frac{cal}{g^{0}c})(86.5^{0}c-31.9^{0}c)$

$=(68.7g)*(31.9^{0}c-19.5^{0}c)$

$\frac{385.78176}{851.88}=\frac{(851.88g^{0}c)}{851.88}$

$=0.45286g^{0}c$

$=0.45\frac{cal}{g^{0}c}$.