Question

A copper of mass 110g is immersed totally in measuring cylinder containing water level rises from 50cm³ to 70m³, what the density of the body

Answer 1

Answer:

density= mass /volume = 110/20 g/m³ = 5.5 g/m³

Explanation:

Please check your question

In place of 50cm³ 50m³

Answer 2

Given :

• Mass of the copper = 110g
• Volume of water (without copper) = 50cm³
• Volume of water+copper = 70cm³

To Find :

• The density of the copper ?

Formula To Be used :

We will use the formula of density :

$\displaystyle \rm \bull \: \rho = \frac{mass}{volume}$

Concept:

As I had answered in the last question also, you should subtract the volume of other quantities from the total volume to get the volume of desired object.

So, we will subtract the volume if water from total volume to find the volume of copper

Using the volume and mass of copper, we can easily find the density

Solution:

Given, Mass of copper = 110g

Volume of Water = 50cm³

Volume of (Water+Copper) = 70cm³

So, Volume if copper = Total-Water

$\displaystyle \rm \implies volume = 70 - 50$

$\displaystyle \rm \implies volume = 20c {m}^{3}$

So, Volume of Copper = 20cm³

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Now, As Given:

Mass of copper = 110g

Volume of Copper = 20cm³

So, using the formula Above stated:

$\displaystyle \rm \implies \rho = \frac{mass}{volume}$

$\displaystyle \rm \implies \rho = \frac{110g}{20}$

$\blue{ \underline{ \boxed{\implies \displaystyle \rm \rho = 5.5 \: gpc {m}^{3} }}}$

So, the density of Copper = 5.5g/cm³

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Final Answer:

• The Density of Copper = 5.5 g/cm³