Physics, asked by SomaanJ94991, 1 year ago

A copper penny has a mass of 32 g. being electrically neutral, it contains equal amounts of positive and negative charges. What is the magnitude of these charges in C. A copper atom has a positive nuclear charge of 3x10^-26 C. Atomic weight of copper is 64g/mole and Avogadro’s number is 6x10^–26 atoms/mole.​

Answers

Answered by aristocles
3

Answer:

Total amount of positive charge in copper penny is

Q = 1.4 \times 10^6 C

Total amount of negative charge in one copper penny is

Q = -1.4 \times 10^6 C

Explanation:

mass of the copper penny is given as

m = 32 g

molar mass of the copper penny is given as

M = 64 g/mol

now total number of moles present in it

n = \frac{32}{64} = 0.5 moles

total number of copper atoms in the given penny is

N = moles \times N_a

N = 0.5(6 \times 10^{23}

N = 3 \times 10^{23}

Now we know that each copper atom has 29 protons and 29 electrons

so total positive charge in each atom is given as

q = N e

q = 29(1.6 \times 10^{-19})

q = 4.64 \times 10^{-18} C

Total charge in one copper penny is given as

Q = (3 \times 10^{23})(4.64 \times 10^{-18})

Q = 1.4 \times 10^6 C

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Topic : Properties of Charge

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