a copper piece whose mass is 88gm and its volume is 10cm³. find its density in kg/m³.
don't give wrong answer
Answers
Answered by
40
➠ANSWER:
- Density = 8800 kg/m³
➠GIVEN:
◉Mass = 88 g
◉Volume = 10 cm³
➠TO FIND:
◉Density in kg/m³
➠CONVERSIONS:
1 g = 0.001 kg => 88 g = 0.088 kg
1 cm³ = 10^{-6}10 -⁶
m³ => 10 cm³ = 10^{-5}10 -⁶m³
➠FORMULA:
- DENSITY = MASS / VOLUME
➠EXPLANATION:
Density = 0.088/ {10}^{-5}10 -⁵
Density = 0.088 × {10}^{5}10 ⁵
Density = 8800 kg/m³
➠points to be noted....
- Density can also be expressed in g/cm³.
- g/cm³ is the CGS unit.
- Expressing density in g/m³ and kg/cm³ is often rare. As they are not standard form of expressing density.
Answered by
4
Answer:
Given that,
Volume of body V=10
−4 m 3
Density of iron, ρ i
=7800kgm −3
Density of water ρw
=1000kgm
−3
Weight in air,W
a
=ρ
i
Vg=7800×10
−4
×10=7.8N
We know that,
Weight in water = weight in air – buoyancy force
W
w
=W
a −ρ
wVgWw
=7.8−1000×10 −4 ×10W w
=6.8N
Hence, the weight of body in water is 6.8 N
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